If it's not what You are looking for type in the equation solver your own equation and let us solve it.
d in (-oo:+oo)
5*d-(d*((10*d^2)/5)) = 0
5*d-2*d^3 = 0
5*d-2*d^3 = 0
d*(5-2*d^2) = 0
-2*d^2 = -5 // : -2
d^2 = 5/2
d^2 = 5/2 // ^ 1/2
abs(d) = (5/2)^(1/2)
d = (5/2)^(1/2) or d = -(5/2)^(1/2)
d = 0
d = 0
d in { (5/2)^(1/2), -(5/2)^(1/2), 0 }
| 5+2x+8-x= | | -6x-78=8x+48 | | m+2+3m-2= | | -7x-14=22-5x | | -20x^2y^4+8xy^4+12y^4=0 | | 81-(y+1)2=0 | | -45-6x=95+8x | | 6x^2y-40xy^2+56y^3=0 | | 3x+x+4=16 | | -x-55=-5x+25 | | ((4x^3)/3)-x^4 | | (1)=-8 | | 4x-14=-6x+20 | | 8+x+x=20 | | (0)=-8 | | 6x^2y+22xy-40y=0 | | (5)=-8 | | (X+3)(5-2x)=0 | | -5x-27=3x+61 | | 5x-4+(x-4)=16 | | y=(1)+6 | | 25=2.50+2.0m | | 24x^2+20xy-24y^2=0 | | y=(6)+6 | | log(4x+18)=2 | | y=(2)+6 | | 3/4(4)-2=y | | 2x-66=-6x+94 | | 3/4(3)-2=y | | 2/9p=4 | | 3/4(1)-2=y | | 3/4(0)-2=y |